Constant speed: \( d = 60 \times 20 = 1200 \, \text{m} \).

February 22, 2026

$Constant speed: \( d = 60 \times 20 = 1200 \, \text{m} \).$

Related Articles

#### 14.31
A car accelerates uniformly from rest to 60 m/s in 10 seconds, then maintains constant speed for 20 seconds, and finally decelerates uniformly to rest in 5 seconds. What is the total distance traveled?
Acceleration phase: \( a = \frac{60}{10} = 6 \, \text{m/s}^2 \); distance \( = \frac{1}{2} \times 6 \times 10^2 = 300 \, \text{m} \).
Deceleration phase: \( a = \frac{-60}{5} = -12 \, \text{m/s}^2 \); distance \( = 60 \times 5 + \frac{1}{2}(-12)(5^2) = 300 - 150 = 150 \, \text{m} \).
Total distance \( = 300 + 1200 + 150 = 1650 \, \text{m} \).
#### 1650

Trending Articles